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Today weβre discussing the common emitter amplifier. Can anyone tell me what components we typically use in this setup?
I think we use transistors and resistors.
Exactly! Transistors serve as the amplifying devices, and resistors help establish our biasing conditions.
Whatβs the role of the current mirror in this configuration?
Great question! The current mirror helps to ensure that the collector currents of our transistors are matched, maintaining consistent performance.
How do we ensure these currents are equal?
By adjusting our bias resistances, we can control the base currents, ensuring they lead to equal collector currents in ideal conditions.
In summary, current mirroring helps stabilize our amplifier's performance by ensuring that our collector currents flow equally through the transistors.
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Now, letβs delve into calculating the biasing resistances. If we want a collector current of 2 mA, what can we infer about our beta value?
With a beta of 100, I think the base current will be 20 microamps.
Exactly! We calculate base current through I_b = I_c / B2.
How do we find the resistance values R1 and R2?
Using Ohm's Law, we can compute these based on our biasing current and supply voltage.
What was the value of R1 and R2 that you mentioned earlier?
They are calculated to be approximately 570 kΞ© each. This ensures we maintain that 20 Β΅A base current.
In summary, biasing ensures that our transistors remain in the active region, which is essential for reliable amplification.
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Letβs talk about output voltage. Can anyone tell me why itβs important to consider base current losses?
Because they can affect the current through the transistors?
Exactly! If we neglect this factor, we risk miscalculating the output voltage.
What happens if currents become mismatched?
The output voltage will vary, potentially leading to significant practical implications, such as shifting the transistor into saturation.
How do we calculate the voltage variation?
We utilize the formula for output resistance and current difference to estimate thisβvery crucial in real-world applications.
In summary, understanding these variations helps us design better amplifiers and ensure consistent performance.
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Focusing on the common emitter amplifier, this section explains the relationship between biasing, current mirroring, and voltage variations, particularly how incorrect assumptions regarding currents can affect output voltage.
In this section, we explore the essential workings of a common emitter amplifier, utilizing current mirrors to bias transistors effectively. The analysis begins with an assumption of perfect mirroring where currents through transistorsβspecifically, transistors 1, 2, 3, and 4βare deemed identical. This method allows us to establish relationships between the collector currents and biasing resistances (R1 and R2).
The section illustrates the calculation of these resistances to achieve a collector current of 2 mA for transistor-1, derived based on current gains defined by the beta (B2) of 100. The computed resistance values, along with early voltage considerations, help to understand the voltage gain which reaches approximately 1923, indicating a high output resistance of 25 kA.
However, in practical scenarios, when considering non-ideal conditions that affect beta values and current flow in transistors, discrepancies in output voltage arise. Consequently, the importance of precision in biasing current through careful consideration of both base currents and early voltage becomes apparent. Mismatched currents can significantly influence voltage variation, with real-world implications of such discrepancies highlighted through numerical examples.
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As I said that the current flow current flow here and here should be equal and if you see it carefully the DC voltage here it is defined by this V β V drop. So, I should say the voltage here it is 12 V. So, the voltage here it is 12 β 0.6 so, that is 11.4 V.
In this chunk, we are discussing the requirement for balance in current flow through different transistors (specifically through the current mirror). The text indicates that the DC voltage can be determined using the drop across the transistors. Given the specified values (12V and 0.6V), we find the voltage at the node is 11.4V. This balance in current flow is crucial for the proper operation of amplifiers using current mirrors.
Think of a water flow system where you have two pipes (transistors) connected to a reservoir (the voltage supply). For the system to work efficiently, the water flow (current) through both pipes must be equal. If one pipe is clogged (higher resistance), it will not allow the same amount of water to flow, changing the pressure (voltage) recorded downstream.
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Now, with this 11.4 V here we can say that whatever the current we do have. So, that may be 2 m which is of course, 1 approximation that we are assuming ( ) = 1 please stop here.
This segment explains that at the node voltage of 11.4V, we can determine the collector current (2 mA) flowing through the transistors, allowing for the assumption that they are operating similarly. This mirroring behavior is essential as it demonstrates how the current in one transistor reflects that in another, facilitating consistent performance in circuits.
Imagine two identical water fountains. If the gauge shows that one fountain is pouring out 2 liters of water per minute (2 mA), we can assume the second fountain, which is designed the same way, will pour out the same amount of water if it's condition remains unchanged. The idea of mirroring current is just like this; both systems should respond the same way under the same conditions.
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So, that gives us the DC output voltage V = 11.4 V right. But of course, if the values of early voltage or in case we cannot ignore say this base current and then of course, the corresponding the current here and here there will be a mismatch and the DC voltage here it will deviate from here.
In this part, the text conveys that the calculated output voltage is 11.4V under ideal conditions. However, it warns that practical scenarios (such as variations in early voltage or base current effects) can lead to mismatches in current flow, resulting in a deviation from this voltage. This introduces the importance of considering real-world imperfections in circuit design.
Consider a light fixture that is supposed to shine at 11.4 lumens (similar to our voltage). If the bulbs you use differ slightly in power (like mismatched early voltage) or if the wiring has weak spots (analogous to base current), the actual brightness may vary, and not all bulbs will shine evenly. Understanding these imperfections is key to achieving desired outcomes.
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In fact, this is the non-ideality factor is . And then the corresponding DC voltage it is given here yeah. So, that is how you can approach.
This final segment discusses how imperfections in current matching can affect the DC voltage at the output. Specifically, the text hints at a factor of non-ideality that complicates the calculation of DC output voltage. This reinforces the importance of precise component values in designing robust electronic circuits.
Imagine baking a cake where the ingredients are not mixed evenly (non-ideality). If the flour is unevenly distributed, parts of the cake may be denser or fluffier than others, affecting the overall taste and appearance. In electronics, if the currents through the components are not matched precisely, the overall performance can be negatively impacted, leading to inconsistencies.
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Key Concepts
Collector Current Equivalence: The collector current of one transistor is mirrored to another through current mirroring.
Voltage Gain Calculation: Voltage gain is calculated based on the relationship between output resistance and input current.
Impact of Beta: Variations in beta affect the base and collector currents, thereby impacting overall output voltage.
See how the concepts apply in real-world scenarios to understand their practical implications.
When the current mirror ensures that transistor-1 and transistor-4 carry an equal collector current, we can calculate the output voltage directly from circuit configuration.
Suppose base current losses cannot be neglected; this requires us to adjust our output voltage calculations accordingly, leading to voltage variation.
Use mnemonics, acronyms, or visual cues to help remember key information more easily.
In an amplifierβs core, the currents must align, to keep the output voltage perfectly fine.
Imagine two friends, Transistor_1 and Transistor_4, running identical races. They both aim for the finish line together, ensuring equal currents through their paths.
Use 'MC' for 'Mirror Consistency' in remembering the purpose of current mirrors.
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Review the Definitions for terms.
Term: Common Emitter Amplifier
Definition:
An amplifier configuration that provides high gain and is commonly used in analog circuits.
Term: Current Mirror
Definition:
A circuit that mirrors current from one active device to another, ensuring consistent current flow.
Term: Bias Resistor
Definition:
A resistor used to establish the correct operating point for a transistor.
Term: Collector Current
Definition:
The current flowing through the collector terminal of a transistor.
Term: Base Current
Definition:
The current flowing into the base terminal of a transistor, crucial for determining its operation.