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Today, weβre going to discuss how current mirrors are used in amplifiers. Can anyone tell me what a current mirror does?
Isn't it a circuit that copies current from one branch to another?
Exactly! It helps in setting consistent bias currents across different transistors. Now, how do we ensure the collector currents in our circuit remain the same?
We have to make sure the currents through the biasing resistors are properly calculated, right?
Thatβs correct! We use Ohmβs law to determine the necessary resistor values. Let's remember the formula for current through a resistor: I = V/R.
So, if we want 2 mA through the collector, we need the BASE currents and resistors to ensure that?
Yes! The base current must correspond with the required collector current given the Ξ² value of the transistors involved.
In summary, we need precise biasing to ensure equal currents that are vital for our amplifier's performance.
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Letβs explore how we calculate the collector current, starting with transistor-1. Given it has a Ξ² of 100, how can we find I_B?
If I_C is 2 mA, then I_B will be I_C/Ξ², right?
Precisely! So, 2 mA divided by 100 gives us 20 Β΅A for I_B. Now, what implications does this have for our resistors R1 and R2?
We should have both resistors set to produce this base current consistently?
Thatβs correct! The calculations lead us to set both R1 and R2 to approximately 570 kβ¦.
And this means we can mirror that current into transistor-4 accurately?
Exactly! The alignment of currents allows us to maintain stability within the amplifier. Always remember the connection between Ξ² and I_B for accurate biasing.
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Having calculated the collector currents, we need to discuss the output resistance. Can anyone remember the formula for output resistance in this context?
Is it the parallel combination of r_o1 and r_o4 for the output impedance?
Correct! And if both are about 50 kβ¦, what would that give us?
That should result in an output resistance of around 25 kβ¦.
Well done! Now, letβs consider the voltage gain β what would we calculate based on our output resistance?
Using the gain equation, with our calculated values, we can expect a gain near 2000?
Exactly! This high gain is a hallmark of amplifiers using active loads. However, remember the role of Early voltage in determining the actual output voltage as well!
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Real-world scenarios often introduce variables like base current loss. How does this affect our calculations?
It might lead to discrepancies in our intended collector currents!
Exactly. If we have higher Ξ² values in transistors. Reflecting on the impact on output voltage, what happens if the required current exceeds what our circuit provides?
Then the output voltage will drop below what we calculated, right?
Right! This highlights the significance of precise calculations in amplifier design, as small differences can lead to larger impacts in voltage output.
So, we need to maintain close tolerances when designing such circuits?
Absolutely! Balancing all these variables ensures our amplifier functions effectively and reliably. Great discussions today!
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The section discusses the principles of a common emitter amplifier using current mirrors, emphasizing the calculations of collector currents in various transistors, the setup of resistors to achieve the desired currents, and the implications for output resistance and voltage gain.
In this section, we delve into the workings of a common emitter amplifier that employs current mirrors for biasing. The discussion begins with the assumption that the transistors in the circuit are identical, enabling straightforward calculations of collector currents. The section illustrates how to calculate the collector current of transistor-1 (I_C1
) and the collector current of transistor-4 (I_C4
), ensuring that they match in value (2 mA). Given the common beta value (β=100) of the transistors, the required biasing resistors (R1 and R2) to establish a normalized base current are also calculated, resulting in a value of approximately 570 k⦠for both resistors.
Furthermore, the small signal output resistance and voltage gain of the amplifier are evaluated under the assumption that all devices are operating in the active region. The calculations produced an output resistance of 25 k⦠and a remarkably high voltage gain close to 2000, confirming the performance expected from an active load configuration.
The section also discusses the significance of Early voltage in determining DC output voltage and the dependency of the currents between the various transistors while taking into account possible mismatches and base current losses. A subsequent example highlights how increased Ξ² values in transistors affect the output voltage and current flows. Overall, this section reinforces essential concepts in amplifier design and introduces practical calculation techniques for performance parameters.
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To get the I_c current of transistor-1 and collector current of transistor-4 to be equal, we want the current flow through transistor-2 to be equal to the current flow through transistor-1. Since Q1 and Q2 are identical having the same Ξ² value of 100, the values of bias resistance R1 and R2 should also be identical.
In this chunk, we are discussing how to set up a circuit involving multiple transistors. Specifically, it highlights the importance of ensuring that certain parameters (like the collector currents of two transistors) match. This is crucial for maintaining consistency in circuit operation. The statement also clarifies that since both transistors Q1 and Q2 are identical, the resistance values in the setup must also be equal to ensure the same biasing condition for both transistors.
Imagine you're trying to perfectly balance two scales with weights. If each scale is identical, you need to use the same weight on each side to keep them level. Similarly, in electronic circuits, using identical components with the same ratings ensures that they function harmoniously without uneven distributions of current.
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To get the value of resistance R1 to achieve I_C = 2 mA, since Ξ² = 100, the base current I_B should be = 20 Β΅A. Therefore, R1 should be calculated such that R1 = V_BE / I_B = 570 kβ¦.
In this section, the focus is on calculating the appropriate resistance to achieve a specified collector current. It elaborates on how the base current and transistor parameters lead to this calculation. By recognizing that the base current influences the overall collector current, the calculation gives students a formula to work with, specifically using Ohmβs law to derive the value of the bias resistor R1.
Think of a gardening analogy: to grow a plant to a specific height, you must give it the right amount of water and nutrients. If you measure and adjust those inputs just right, the plant will grow as expected. Similarly, in electronics, by calculating the right 'inputs' (like the resistance based on the collector current), you can ensure the output (the current through the transistor) meets your expectations.
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Assuming base current loss is negligible, we conclude that the collector current of transistor-3 is also 2 mA, which is mirrored to transistor-4, leading to Q4 also having a collector current of 2 mA.
This chunk explains the matching of currents between transistors and the implications of assuming negligible base current loss. In practice, this means that the design can lead to reliable circuit behavior since the mirrored current in transistor-4 reflects the originally set current of 2 mA from transistor-3. This concept is central to understanding how transistors interact in a circuit and helps in predicting the behavior of multiple-device arrangements.
Imagine a relay race where one racer hands off a baton to their teammate. If the first racer runs effectively and hands off the baton smoothly, the next racer can take off at the same speed as the first one. Similarly, in the circuit, when the current is handed off correctly from one transistor to another, both can perform optimally.
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We assume both devices are in active region, defining output resistance R_out similarly as R_o1 and R_o4, where R_o1 = 50 kβ¦. This leads to an output resistance of 25 kβ¦ when considering both transistors together. The voltage gain is then calculated as g_m * R_out.
This chunk introduces the concepts of output resistance and voltage gain in transistor circuits. It explains how to calculate the output resistance from given transistor characteristics and how this affects the overall gain of the amplifier. The voltage gain formula indicates how effectively the amplifier can manage input signals, which is crucial for students studying amplifier design.
Think of an amplifier as a speaker. The output resistance can be likened to how easily the speaker can give sound output. If it's too low, it may not project the sound well, just like in a circuit where low output resistance can hinder efficiency. Understanding how to manipulate these parameters can help in creating a powerful amplifier, similar to making a louder speaker.
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The DC output voltage is derived considering the V_BE drop, resulting in a DC voltage V_OUT = 11.4 V. However, if there's a significant base current or early voltage mismatch, this output voltage can deviate significantly.
This chunk covers the importance of calculating the DC output voltage based on the voltage drops across the transistors. It illustrates how the idealized calculations may vary with real-world effects, such as mismatched parameters like base current or early voltage. This discussion helps students understand that theoretical predictions must often be adjusted in practical scenarios.
Picture assembling a jigsaw puzzle. If all the pieces fit together perfectly, you complete the picture easily, just like achieving the ideal voltage. However, if some pieces don't fit due to mismatched shapes, it makes completing the picture much harder. Similarly, in electronics, the ideal calculations must always consider real-world variations that can affect the final outcome.
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Key Concepts
Current Mirror: A circuit configuration designed to copy current from one branch of the circuit to another.
Collector Current: The output current taken from a transistor's collector, essential for amplifier functionality.
Bias Resistors: Resistors used to set the base current in transistors, influencing stability and performance.
Voltage Gain: Reflects the amplifier's ability to increase the amplitude of a signal, critical for audio and signal processing.
Early Voltage: Impacts the output characteristics of transistors and needs to be considered in practical scenarios.
See how the concepts apply in real-world scenarios to understand their practical implications.
In designing a common emitter amplifier, ensuring that R1 = R2 = 570 k⦠leads to a stable I_C1 = I_C4 = 2 mA.
The calculated output resistance of 25 k⦠indicates a stable design, while the expected voltage gain of approximately 2000 shows performance efficiency.
Use mnemonics, acronyms, or visual cues to help remember key information more easily.
In circuits of mirrors with currents so bright, Biasing is key to make transistors right.
Imagine a group of identical twins, each in charge of a current stream. They need to work together to keep the flows equal, just like how transistors use current mirrors to maintain balanced outputs in amplifiers.
C.B.A. - Remember: Collector, Base, Amplifier functions in amplifying circuits for clarity!
Review key concepts with flashcards.
Review the Definitions for terms.
Term: Collector Current (I_C)
Definition:
The current flowing from the collector of a transistor, which is controlled by the base current.
Term: Bias Current
Definition:
A steady current applied to the base of a transistor to keep it in the active region.
Term: Early Voltage (V_A)
Definition:
A parameter that quantifies the output conductance in a transistor, impacting its performance by affecting the collector voltage.
Term: Voltage Gain (A_v)
Definition:
The ratio of output voltage to input voltage in an amplifier, representing its amplification capability.
Term: Active Region
Definition:
The operating region of a transistor where it acts as an amplifier rather than a switch.