Gain Calculation - 88.4.5 | 88. Numerical examples on current mirror and its applications (Part-C) | Analog Electronic Circuits - Vol 4
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Interactive Audio Lesson

Listen to a student-teacher conversation explaining the topic in a relatable way.

Current Mirror Basics

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Teacher
Teacher

Let's discuss the role of current mirrors in amplifiers. Current mirrors are primarily used to bias active loads, ensuring consistency in current levels across transistors.

Student 1
Student 1

Why is it important for the transistors to be identical?

Teacher
Teacher

Great question! Having identical transistors, like Q1 and Q2, ensures their beta values match, which is crucial for achieving equal collector currents.

Student 2
Student 2

What happens if they’re not identical?

Teacher
Teacher

If they’re not identical, we'll see variations in current which could lead to mismatched output conditions and affect amplifier performance.

Calculating Resistances

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Teacher
Teacher

Let’s calculate the biasing resistance needed to achieve a collector current of 2 mA. Can anyone remind me how to find the base current?

Student 3
Student 3

Isn’t it the collector current divided by beta?

Teacher
Teacher

Exactly! For Ξ² equal to 100, the base current is 20 Β΅A, leading us to derive that the resistors should be approximately 570 kΞ©.

Student 4
Student 4

How do we confirm that this will yield a 2 mA collector current?

Teacher
Teacher

By ensuring that both transistors are matched and operating in their active regions, we connect these resistors to maintain steady current flow!

Output Resistance and Voltage Gain

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Teacher
Teacher

Next, let’s find the small signal output resistance. Using values from our transistors, we find that the output resistance is 25 kΞ©.

Student 1
Student 1

What does that mean for our amplifier's performance?

Teacher
Teacher

The higher the output resistance, typically, the better the voltage gain we can achieve. Here, it leads us to a voltage gain of about 1923!

Student 2
Student 2

What’s the significance of such high gain?

Teacher
Teacher

High voltage gain indicates excellent amplification capabilities, a primary objective in many amplifier designs!

Understanding Voltage Output Variations

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Teacher
Teacher

Lastly, we cover the DC output voltage. It's calculated under the assumption that the early voltage impacts the current levels.

Student 3
Student 3

How do we assess the impact of early voltage effectively?

Teacher
Teacher

We correlate the expected output current with the actual active region behavior of our transistors, adjusting for observed variations.

Student 4
Student 4

So, it’s crucial to consider all these factors for real-world applications?

Teacher
Teacher

Absolutely! Practical amplification requires thorough analysis of all elements in circuit conditions to ensure reliable performance.

Introduction & Overview

Read a summary of the section's main ideas. Choose from Basic, Medium, or Detailed.

Quick Overview

This section discusses gain calculation in common emitter amplifiers using current mirrors to bias active loads.

Standard

The section covers how current mirrors are used in common emitter amplifiers for biasing active loads, including calculations for collector currents, small signal output resistance, and voltage gain, emphasizing the significance of early voltage and beta values.

Detailed

Gain Calculation

In analog electronic circuits, particularly when utilizing common emitter amplifiers with current mirrors, obtaining precise gain calculations is essential for understanding amplifier performance. In this section, we detail the configuration where current flows through various transistors including Q1, Q2, Q3, and Q4. We emphasize that for biasing the active load of transistor Q4, it is crucial to maintain equal collector currents in the relevant transistors, facilitating transistor matching and ensuring they operate within their active regions.

Identical Conditions and Parameters: We assume that all transistors are identical with a beta (Ξ²) of 100, ensuring comparable current levels. With these properties defined, we calculate the biasing resistors needed to achieve a collector current of 2 mA, showing that the necessary resistors can be calculated to be approximately 570 kΞ©.

Output Resistance Calculation: Additionally, we derive the small signal output resistance and voltage gain, considering both transistors Q1 and Q4 operate in their active regions. The calculated output resistance stands at 25 kΞ©, showcasing the relationship between the transistor models and their operating conditions.

Voltage Gain: The voltage gain of the amplifier, calculated to be approximately 1923, reflects the efficiency of the circuit design, highlighting the benefits of using active load techniques with current mirrors to enhance amplifier performance.

DC Output Voltage Considerations: Subsequently, we dive deeper into calculating the DC output voltage, emphasizing how adjustments can lead to variations in current due to differing base current losses. The influence of the early voltage is critical in this context, as mismatch can lead to substantial changes in the desired output voltage.

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Analog Electronic Circuits _ by Prof. Shanthi Pavan
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Audio Book

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Output Resistance Calculation

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Now, with this information let us try to find the small signal output resistance and voltage gain of the amplifier. So, we are assuming both the devices are in active region. So, the output resistance R = r β«½ r . Whereas, this r , r = = . So, that is giving us 50 kΩ.

Detailed Explanation

In this chunk, we're focusing on how to determine the output resistance of a common emitter amplifier with a current mirror. The output resistance is a crucial parameter, as it directly influences the amplifier's ability to drive loads. The parameters 'r' represent the small signal output resistances of the individual transistors in the amplifier. When the transistors are in the active region, these resistances can be combined using the formula R = r1 || r2 (the parallel combination) to obtain the overall output resistance. By calculating this value, we can better understand how the amplifier will perform under various load conditions.

Examples & Analogies

Think of the output resistance like the pressure in a water pipe. A higher resistance means that it's harder for water (or, in this case, electrical signals) to flow through. If you have two pipes (transistors) working together, their combined ability to allow water flow (output resistance) changes based on how they are connected (in parallel). Just like how you might use larger pipes to reduce pressure for easier flow, understanding output resistance helps ensure your amplifier can deliver signals efficiently.

Voltage Gain Calculation

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Now we like to get what will be the gain of this amplifier. So, the gain of the amplifier of course, the voltage gain of this amplifier it is g R with a β€’ sign. So, what is the value of the g ? So, that is , that is the V given there. So, this = β„§. So, the voltage gain so, the voltage gain it is , it is close to 2000 rather yeah. So, the gain it is coming 1923.

Detailed Explanation

This part of the section discusses how to compute the voltage gain of the amplifier. The voltage gain (denoted as 'A') indicates how much the output voltage increases compared to the input voltage. The formula used involves the transconductance ('g') of the first transistor and the output resistance. Here, the voltage gain was found to be approximately 1923, indicating a high amplification factor. This signifies that small changes in input voltage result in significant changes in the output voltage, a desirable characteristic for amplifiers.

Examples & Analogies

Imagine you are using a microphone to amplify your voice. The microphone converts your voice (input voltage) into an electrical signal, which then gets amplified by an amplifier (the voltage gain) before it comes out of the speakers (output voltage). If the amplifier has a high voltage gain of 1923, it means even a soft whisper will come out as a loud voice from the speakers. This characteristic is crucial in applications where it is essential to boost weak signals to a more usable level.

Understanding DC Output Voltage

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So, as I said that the current flow current flow here and here should be equal and if you see it carefully the DC voltage here it is defined by this V β€’ V drop.

Detailed Explanation

In this section, we delve into the concept of DC output voltage in the context of a common emitter amplifier. The output voltage is determined by the difference between the supply voltage (Vcc) and the voltage drop across the base-emitter junction of the transistor. In this case, the voltage drop is typically around 0.6 to 0.7V for silicon transistors. Thus, if we have a supply voltage of 12V and a base-emitter drop of 0.6V, the output voltage will be approximately 11.4V. Understanding this relationship is critical for designing amplifiers that deliver the intended output while maintaining stability.

Examples & Analogies

Consider the water tank analogy where the supply voltage is like the water level in a tank. As water flows out (current flow), the water level decreases, similar to how voltage drops across components in an electronic circuit. Knowing the level helps us ensure there’s enough water pressure for the intended usage, just as understanding DC output voltage helps ensure the amplifier has a sufficient level to perform its function effectively.

Definitions & Key Concepts

Learn essential terms and foundational ideas that form the basis of the topic.

Key Concepts

  • Current Mirroring: Essential for maintaining constant bias currents in amplifier design.

  • Collector Current: Crucial for ensuring that output currents match expected values in amplifier circuits.

  • Beta (Ξ²): A defining factor in determining transistor performance and current amplification.

  • Voltage Gain: Reflects the ability of an amplifier to boost the input signal, a primary function in analog circuits.

  • Early Voltage: Influences the output resistance and current characteristics in amplifier applications.

Examples & Real-Life Applications

See how the concepts apply in real-world scenarios to understand their practical implications.

Examples

  • Using the assumed Ξ² of 100, if the collector current is set to 2 mA, the corresponding base current can be calculated as 20 Β΅A.

  • In a designed common emitter amplifier with specified active resistors, the output voltage gain can be calculated close to 1923.

Memory Aids

Use mnemonics, acronyms, or visual cues to help remember key information more easily.

🎡 Rhymes Time

  • For stable current, use a mirror, it keeps the signals flowing clearer!

πŸ“– Fascinating Stories

  • Imagine a team of runners, each one representing a transistor. If they all run at the same speed (current), they’ll finish together, just like the current mirror ensures equal currents across transistors!

🧠 Other Memory Gems

  • C.B.V.E (Collector, Base, Voltage, Early) - remember the essentials in transistor functioning.

🎯 Super Acronyms

G.E.C (Gain, Early Voltage, Collector current) - key factors determining amplifier performance.

Flash Cards

Review key concepts with flashcards.

Glossary of Terms

Review the Definitions for terms.

  • Term: Current Mirror

    Definition:

    A circuit configuration designed to copy a current through one active device to another, maintaining consistency.

  • Term: Collector Current

    Definition:

    The current that flows through the collector terminal of a transistor, utilized for amplification.

  • Term: Beta (Ξ²)

    Definition:

    The current gain factor of a transistor, represented as the ratio of collector current to base current.

  • Term: Voltage Gain

    Definition:

    The ratio of output voltage to input voltage in an amplifier, indicating how much the amplifier increases the input signal.

  • Term: Early Voltage

    Definition:

    A parameter of bipolar junction transistors that indicates the output resistance of the device, related to its current gain.