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Today we will explore the current mirror and its significance in designing common emitter amplifiers. Can anyone tell me what a current mirror does?
Isn't it used to provide a constant current regardless of the load?
Exactly! So when we use it in an amplifier, it helps maintain a steady current through the active load. Now, how do we ensure that transistors are matched?
I think we have to use identical transistors, right?
Correct! Using identical transistors ensures balanced performance. Now, letβs discuss biasing resistances.
What happens if the resistances aren't matched?
Great question! Mismatched resistances can result in unequal current flow, affecting amplifier stability. Letβs summarize: current mirrors help provide a constant current and require matched components for optimal performance.
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In our example, we wanted both collector current I_C1 and I_C4 to be equal. How do we calculate the required bias resistance?
We need to make sure the base currents are equal, right?
Yes, we can ignore the base current losses if we assume high beta. Can anyone remind me of the required current flow for our example?
The current was supposed to be 2 mA?
Correct! And to achieve this with a Ξ² of 100, we calculated resistance values to maintain that current. Now, what's the significance of the Early voltage?
Isn't it to account for variations in the output characteristic?
Exactly! The Early voltage ensures our calculations remain accurate by accounting for non-idealities. Letβs reaffirm this lesson; matching parameters is critical for stability in electronic circuits.
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Now, letβs dive into computing the voltage gain of our amplifier. Our derived voltage gain was about 1923. Can anyone explain why high gain is expected here?
Because of the active load design, it significantly boosts the voltage!
Absolutely! High output resistance aids in achieving that high voltage gain. Now, let's differentiate between DC output voltage and AC signals.
Does the DC output voltage change with the collector current?
Exactly! If our transistors are mismatched, it can lead to a voltage drop, requiring us to lower our output voltage. Does anyone recall what our final output voltage was?
Wasn't it 11.4 V before considering mismatches?
Right! Itβs crucial to take those deviations into account in practical designs. Remember, accuracy in current reflection determines overall performance.
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It delves into the concept of current mirrors applied in common emitter amplifiers, illustrating the theory with practical numerical examples that entail calculations of resistances, collector current, small signal output resistance, voltage gain, and the significance of early voltage. The section serves as a precursor to applying these concepts in differential amplifiers.
This section focuses on the application of current mirrors within common emitter amplifiers, using practical numerical examples to better understand the design and analysis of these circuits. The lecture introduces concepts such as the current through each transistor, the necessity for matched transistor characteristics, and the calculations needed for biasing resistances and output voltages. The determinants of small-signal output resistance and voltage gain are explored as well, emphasizing the importance of precision in current mirroring to maintain circuit performance. The section aims to provide stepping stones towards more complex applications such as differential amplifiers, preparing students for a deeper understanding of electronic circuit design.
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So, we are going through different numerical examples and now we are going to talk about one common emitter amplifier which is using current mirror and particularly to bias the active load say Q.
In this initial segment, we are being introduced to the concept of a common emitter amplifier using a current mirror. The common emitter amplifier is a basic but important circuit configuration that allows for voltage amplification. Here, the active load is indicated as transistor Q, which will be explained further in the context of the current mirror's functionality.
Think of the common emitter amplifier like a public announcement system. If you want to amplify a speaker's voice (input), the system uses various electronic components to enhance the sound (amplify) before it comes out of the loudspeakers (output).
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We are using current mirror and transistor-1; it is the amplifying device then we are assuming that Q1 and Q2 are identical and also we are assuming that whatever this Q3 and Q4 are also identical.
This chunk discusses the assumptions made about the identical nature of the transistors in the circuit. To ensure uniform performance, it's critical that Q1, Q2, Q3, and Q4 share similar characteristics. This helps in maintaining consistent current flow and amplification properties in the circuit. The idea is that identical components behave predictably under similar conditions.
Imagine we are assembling a sports team. If all players (transistors in this case) have the same training and skills, the team works effectively together. However, if one player is significantly stronger or weaker, it could disrupt the game (circuit performance).
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So, to get the I current of transistor-1 and collector current or transistor-4 equal. We want the current flow through transistor-2 should be equal to current flow through transistor-1.
Here, the focus shifts to ensuring that specific current levels are adequately matched across the transistors. A key intention is to keep the collector current of transistor-1 (I_C1) same as that of transistor-4. This balance is essential for the effective operation of the current mirror, which stabilizes and controls the overall current flow in the circuit.
Consider a relay race. For the team to perform well, each runner (transistor) must pass the baton (current) smoothly and consistently to the next runner. If one runner is faster, it could disrupt the race.
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So, also we do have othered information namely all the devices are having early voltage 100 V and with this information let we try to find what will be the value of this resistance to get the collector current I_C = 2 mA.
At this point, the focus is on calculating the bias resistance required to achieve the desired collector current of 2 mA. The Early voltage is a critical factor that influences how current behaves in a transistor, impacting the output characteristics and helping in fine-tuning the circuit parameters to achieve optimal performance.
Imagine setting a thermostat in a house. Just like how we adjust the thermostat to maintain a comfortable room temperature (current), here we adjust the resistance to achieve a desired current through the transistors.
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Now with this information let us try to find the small signal output resistance and voltage gain of the amplifier.
This part deals with calculating the small signal output resistance and the voltage gain of the amplifier circuit. The output resistance must be calculated accurately, as it significantly impacts the overall efficiency and gain of the amplifier. Understanding these parameters is crucial for predicting how the amplifier will respond to varying input signals.
Think about how an amplifier works much like an amplifier in a sound system: the stronger the amplifier's signal processing (output resistance and gain), the better the sound quality. If the amplifier has low gain, youβll barely hear the sound despite the volume being up.
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Now we like to get what will be the gain of this amplifier. So, the gain of the amplifier of course, the voltage gain of this amplifier it is g_m R_out with a β sign.
In this chunk, the process of determining the voltage gain is discussed in terms of transconductance (g_m) and output resistance (R_out). The gain itself plays a pivotal role in amplifying the signal, and a negative sign indicates a phase inversion typical of a common emitter configuration, where the output signal is inverted relative to the input signal.
When you turn the volume knob on a radio, a little twist results in a much louder sound; similarly, adjusting the parameters in this amplifier circuit allows for significant amplification of the input signal.
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Key Concepts
Current Mirror: A tool used in amplifiers to maintain current stability.
Biasing: The process of setting a transistor's operating point.
Voltage Gain: The amplified output signal compared to the input.
DC Output Voltage: The voltage level determined by current and circuit configurations.
See how the concepts apply in real-world scenarios to understand their practical implications.
Example of computing bias resistance based on desired collector current.
Example illustrating the relationship between output voltage and early voltage.
Use mnemonics, acronyms, or visual cues to help remember key information more easily.
In a current mirror, currents reflect, maintaining stability is what we expect.
Imagine twin brothers performing the same task. One mirrors the movements; the other follows exactly, ensuring harmony.
MEMO for Current Mirroring: Maintain Equal Matching Output.
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Review the Definitions for terms.
Term: Current Mirror
Definition:
An electronic circuit that copies the current flowing in one active device to another, maintaining accurate current levels.
Term: Common Emitter Amplifier
Definition:
A type of amplifier configuration that provides significant voltage gain from an input signal.
Term: Beta (Ξ²)
Definition:
The current gain factor of a transistor; the ratio of collector current to base current.
Term: Early Voltage
Definition:
A measure of the efficiency of a transistor's output characteristics; factored into voltage gain calculations.
Term: DC Output Voltage
Definition:
The direct current voltage output from a circuit after accounting for losses.
Term: Voltage Gain
Definition:
The ratio of the output voltage to the input voltage in an amplifier.
Term: Output Resistance
Definition:
The resistance seen by the load connected to the output of an amplifier.