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Today, we will explore subsequences and their properties. Can anyone tell me what a strictly increasing sequence is?
Isn't it a sequence where every next number is larger than the previous one?
That's correct! For example, in the sequence (1, 2, 3, 4), every next number is larger. Now, what about a strictly decreasing sequence?
In that case, every number is smaller than the one before it, right?
Exactly! Let's use 'ID for increasing and DD for decreasing.' Remember that as we continue.
So 'ID' can help us distinguish between these types of sequences?
Good job! Now, what is a subsequence?
Is it selecting numbers from a sequence, even if they aren't next to each other?
Yes! For example, in the sequence (1, 3, 0, -5, 2, 8), you can select (1, 2, 8) as a subsequence.
So, it's not necessary to take numbers in a row?
Correct! Sequences can skip numbers and still count as subsequences. Crucial for our next discussion!
Next, let's discuss the pigeonhole principle. Why do you think it’s important here?
It helps show that we have more choices than possibilities.
Exactly! If you have `n + 1` numbers, it guarantees at least one subsequence must exceed a certain length. Can anyone recall what that length is?
Is it `n + 1`?
That's right! Remember: More sequences than lengths.
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The section delves into the significance of subsequences in a given set of distinct real numbers. It explains how any sequence of n + 1
distinct real numbers must contain a subsequence of length n + 1
that is either strictly increasing or strictly decreasing, using principles such as the pigeonhole principle and proof by contradiction.
This section examines how to apply mathematical restrictions on sequences of distinct real numbers to illustrate the existence of subsequences that demonstrate certain properties—specifically, being either strictly increasing or strictly decreasing. The main claim asserts that for any sequence of n + 1
distinct real numbers, there exists a subsequence of length n + 1
that maintains one of these two properties.
n + 1
numbers, at least one subsequence must have a certain length due to the limited options available for pairing the lengths of subsequences. The proof utilizes a contradiction approach to show that if we assume that all increasing and decreasing subsequences do not exceed length n
, we can arrive at a situation where there are more 'pigeons' (subsequence lengths) than 'holes' (potential lengths), guaranteeing a repetition and thus a subsequence of the desired length.
In this way, the section not only presents the main claim but also provides a thorough examination of the logic and proofs involved in establishing it.
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A subsequence means here that the values may not be consecutive. That means I am allowed to miss a few numbers. In the sense, say I take a sequence 1, 3, 0, -5, 2, 8 and so on. Then I can choose to pick 1 and then exclude 3 and 0 and -5. This is a subsequence. In the same way I can pick a subsequence saying 3, 2 and 8 that means I skip 0, I skip -5.
A subsequence is a series of selected elements from a sequence where the order is preserved, but not necessarily consecutive. For example, if we have a sequence like 1, 3, 0, -5, 2, 8, we can create subsequences such as 1, -5, and 2 (by selecting specific numbers) or even 3, 2, and 8 (skipping some numbers in between). The important point is that any selection maintains the original order from the parent sequence.
Imagine you're collecting stickers from a variety of sets. If you have a complete album (the full sequence) but only want to showcase a few highlights at a party, you can choose certain stickers (the subsequence) to display without going in order. Perhaps you choose the first sticker, skip a few, and then grab one from later in the album. Your selection is not consecutive but still reflects what you want to showcase from your collection.
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So what this question basically says is that irrespective of the way your \( n+1 \) distinct real numbers are chosen you always have a subsequence. By that I mean that you have a set of \( n+1 \) values going from left to right but need not be in consecutive locations; some of the locations might be skipped. But the number of values are \( n+1 \) such that if you view those \( n+1 \) values they are either strictly increasing or strictly decreasing.
The claim here is that no matter how you select \( n+1 \) distinct real numbers, there will always be some subsequence of these numbers that is either strictly increasing or strictly decreasing. To clarify, strictly increasing means each next number in the subsequence is larger than the previous one (e.g., 1, 2, 3), while strictly decreasing means each next number is smaller (e.g., 3, 2, 1). This property holds true across various sequences and guarantees the presence of such subsequences.
Think of a race involving runners of varying speeds. Regardless of how they finish (their times can be mixed: some fast, some slow), if you take the finishing order (the sequence), you’ll inevitably find at least one group of runners who finished in increasing speed (the fastest runners) or one that finished in decreasing speed (the slowest). This highlights that regardless of the arrangement, groups with uniform trends are guaranteed.
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So by PHP here I mean pigeonhole principle. So pigeonhole principle guarantees me that you definitely have a pair of values here say \( a_i \) and \( a_j \) such that your \( l_i \) and \( l_j \) are the same.
The Pigeonhole Principle states that if you have more items than containers to put them in, at least one container must hold more than one item. In this context, if you take the lengths of increasing and decreasing subsequences of your distinct numbers, and since there are only \( n \) possible lengths, but you have more sequences, at least one length must repeat. This is crucial for proving that there must be subsequences as described.
Imagine you have ten pairs of shoes but only six shelves to store them. According to the pigeonhole principle, at least one shelf must contain more than one pair of shoes because there are more pairs (pigeons) than places to put them (holes). Similarly, this principle in the sequence of numbers ensures there are repeated lengths of subsequences leading to our conclusions.
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I assume that the statement is false and that means for each \( a_i \) in the sequence, the value \( l_i \) is at most \( n \).
To prove something by contradiction, you assume the opposite of what you want to prove and show that leads to an impossibility. Here, if it were true that every subsequence's lengths are at most \( n \), then when paired with their maximums, you would not have enough unique lengths for each item in your list, leading to a contradiction. It shows the flaw in the original assumption, thus validating the existence of either increasing or decreasing subsequences of the required length.
Consider a classroom of students where each student can only stand on their assigned spot and there are only ten spots for them. If you argue that every student occupies a unique spot without overlaps, but you have twelve students, you reach an impossibility as some students need to share spots. This logic illustrates the contradiction that arises when assuming all sequences meet a condition that they can't possibly meet.
Learn essential terms and foundational ideas that form the basis of the topic.
Key Concepts
Strictly Increasing/Decreasing Sequences: A sequence is strictly increasing if each term is less than the following term, and strictly decreasing if each term is greater than the following term.
Subsequences: A subsequence is formed by selecting certain elements from the original sequence, allowing for non-consecutive elements.
Pigeonhole Principle: This principle is used to demonstrate that with n + 1
numbers, at least one subsequence must have a certain length due to the limited options available for pairing the lengths of subsequences.
The proof utilizes a contradiction approach to show that if we assume that all increasing and decreasing subsequences do not exceed length n
, we can arrive at a situation where there are more 'pigeons' (subsequence lengths) than 'holes' (potential lengths), guaranteeing a repetition and thus a subsequence of the desired length.
In this way, the section not only presents the main claim but also provides a thorough examination of the logic and proofs involved in establishing it.
See how the concepts apply in real-world scenarios to understand their practical implications.
In the sequence (5, 3, 9, 2), (5, 9) is a strictly increasing subsequence.
In the sequence (4, 7, 5, 6), (4, 5) is a strictly increasing subsequence.
Use mnemonics, acronyms, or visual cues to help remember key information more easily.
If upward we climb, the sequence will shine, but downward we fall, it might not be all.
Imagine climbing a mountain; each step up is a number in a strictly increasing sequence—fail to skip, and you'll go down!
For 'I' keep going up and for 'D' keep going down - Remember I for Increase and Decrease!
Review key concepts with flashcards.
Review the Definitions for terms.
Term: Subsequence
Definition:
A sequence derived from another sequence where some elements may be omitted without changing the order.
Term: Strictly Increasing Sequence
Definition:
A sequence where each term is greater than the preceding one.
Term: Strictly Decreasing Sequence
Definition:
A sequence where each term is less than the preceding one.
Term: Pigeonhole Principle
Definition:
A principle stating that if more items are put into fewer containers than there are items, at least one container must contain more than one item.