Exercise 8 - 11.8 | Chapter 3 : Quadrilaterals | CBSE Class 9 Maths
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Interactive Audio Lesson

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Angle Properties of Quadrilaterals

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Teacher
Teacher

Today, we will explore how to find missing angles in a quadrilateral. Remember, the sum of all interior angles in a quadrilateral is always 360Β°.

Student 1
Student 1

What if I know three angles already? How do I find the fourth?

Teacher
Teacher

Great question! You subtract the sum of the known angles from 360Β° to find the missing angle. Let's say the angles are 90Β°, 85Β°, and 95Β°. What do you think the fourth angle would be?

Student 2
Student 2

It would be 360 - (90 + 85 + 95) = 90Β°!

Teacher
Teacher

Exactly! So, remember the formula: Missing angle = 360Β° - (Sum of known angles).

Student 3
Student 3

Can we try another example?

Teacher
Teacher

Sure! If the three angles are 110Β°, 85Β°, and 95Β°. What's the fourth angle?

Student 4
Student 4

The fourth angle would be 360 - (110 + 85 + 95) = 70Β°!

Teacher
Teacher

Excellent! Always remember, angle sum property helps in many ways!

Properties of Parallelograms

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Teacher
Teacher

Now, let’s deepen our understanding of parallelograms. Can someone remind me what properties a parallelogram has?

Student 1
Student 1

Opposite sides are equal and parallel, and opposite angles are equal!

Teacher
Teacher

Correct! Also, the diagonals bisect each other. Can you tell me what that means?

Student 2
Student 2

It means that each diagonal cuts the other into two equal parts.

Student 3
Student 3

So, if one diagonal is 10 cm, would each half be 5 cm?

Teacher
Teacher

Yes! Very well put! Remember, understanding these properties helps with more complex problems later on.

Student 4
Student 4

Can we apply this to find angles if we know one angle?

Teacher
Teacher

Absolutely! For example, if one angle is 60Β°, the opposite angle is also 60Β°, and the adjacent angles will each be 120Β° because they are supplementary. Always think about how these properties connect!

Calculating Area of Quadrilaterals

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Teacher
Teacher

Next, let's look at how to calculate areas of different quadrilaterals. Can anyone tell me the formula for the area of a rectangle?

Student 2
Student 2

Area = Length Γ— Breadth!

Teacher
Teacher

Exactly! And for a square?

Student 3
Student 3

Area = SideΒ².

Teacher
Teacher

Correct! Now what about a parallelogram?

Student 1
Student 1

Area = Base Γ— Height, right?

Teacher
Teacher

Right! And how about a trapezium?

Student 4
Student 4

Area = (1/2) Γ— (Base1 + Base2) Γ— Height!

Teacher
Teacher

Perfect! Always ensure you remember these formulas for solving area-related problems.

Introduction & Overview

Read a summary of the section's main ideas. Choose from Basic, Medium, or Detailed.

Quick Overview

This section covers various exercises focused on the properties and calculations associated with quadrilaterals.

Standard

The exercises in this section challenge students to apply their understanding of quadrilaterals, including calculating angles, verifying properties, and applying formulas for areas. Engage with different difficulty levels to strengthen mathematical reasoning and problem-solving skills.

Detailed

Detailed Summary

This section focuses on a diverse range of exercises aimed at solidifying knowledge and skills related to quadrilaterals. Students will explore tasks that require them to find missing angles, confirm properties of quadrilaterals such as parallelograms and trapeziums, and calculate areas using specific formulas for different quadrilaterals. Each exercise is designed to reinforce the concepts of the chapter, emphasizing not only procedural knowledge but also conceptual understanding of the properties of quadrilaterals. Problems are categorized into easy, medium, and hard levels to accommodate different levels of student comfort and expertise. Through these exercises, students will enhance their analytical skills, allowing them to apply theoretical knowledge practically.

Audio Book

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Exercise 8: Proving Properties of a Rhombus

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The diagonals of a rhombus intersect at right angles. Prove it using properties of parallelograms.

Detailed Explanation

To prove that the diagonals of a rhombus intersect at right angles, we start by using the properties of parallelograms. A rhombus is a special type of parallelogram where all sides are equal. We know that in a parallelogram, the diagonals bisect each other. Let's label the rhombus as ABCD with diagonals AC and BD intersecting at point E. Since E is the midpoint of both diagonals, we can use the properties of triangles formed. By showing the angles AEB and CED are equal, and then using the property of alternate angles, we establish that each angle formed at point E is a right angle.

Examples & Analogies

Imagine a kite flying in the sky. The cross-section of the kite's shape acts just like a rhombus. When the two crossbars of the kite (the diagonals) meet, they form a perfect 'X' shape that divides the kite into four triangular sections, indicating that the angles at which they intersect are all right angles. This real-life observation of a kite helps visualize why the diagonals of a rhombus, like the ones in a kite, intersect perpendicularly.

Exercise 8: Trapezium Angle Calculation

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PQRS is a trapezium with PQ || SR. If ∠P = 70° and ∠Q = 110°, find ∠R and ∠S.

Detailed Explanation

In a trapezium, one pair of sides is parallel (in this case, PQ and SR). The angles on the same side of a trapezium add up to 180°. So, we can find angle R by calculating: ∠R = 180° - ∠P = 180° - 70° = 110°. Similarly, we can find angle S: ∠S = 180° - ∠Q = 180° - 110° = 70°. Therefore, angles R and S measure 110° and 70° respectively.

Examples & Analogies

Think of the trapezium as a slice of pizza with an uneven crust. The two angles at the top (P and Q) represent the toppings on the pizza slice. When you look at the slice from one side, the toppings create a balance where the sum of the angle toppings on one side must match a complementary angle of 180Β°. That's how we calculate angles R and S, ensuring the whole pizza gives a satisfying taste that meets expectations.

Exercise 8: Area Calculation of a Parallelogram

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ABCD is a parallelogram. If the length of AB is 6 cm and the height from D to AB is 4 cm, find the area of the parallelogram.

Detailed Explanation

The area of a parallelogram can be calculated using the formula: Area = Base Γ— Height. Here, the base (length of AB) is 6 cm, and the height from point D to line AB is 4 cm. Thus, the area is calculated as: Area = 6 cm Γ— 4 cm = 24 cmΒ².

Examples & Analogies

Imagine you are laying down a garden plot in the shape of a parallelogram. The long edge of your plot is 6 meters long and you want soil to go 4 meters deep. The area helps you understand how much soil you need to cover the space for planting flowers. In this case, simply multiplying the length by the depth gives you the full expanse required for your gardening project.

Exercise 8: Area Calculation of a Kite

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The diagonals of a kite are 8 cm and 6 cm. Find the area of the kite.

Detailed Explanation

The area of a kite can be calculated using the formula: Area = (1/2) Γ— d1 Γ— d2, where d1 and d2 are the lengths of the diagonals. For this kite, one diagonal is 8 cm, and the other is 6 cm. So, the area calculation will be: Area = (1/2) Γ— 8 cm Γ— 6 cm = 24 cmΒ².

Examples & Analogies

Consider a kite flying high in the sky. If you look at its shape, you can see that it comprises two triangles (formed by the diagonals) glued together at the center. When you want to find out how much fabric was used to make the kite, calculating the area using the diagonals gives you that information. Just like how you’d measure how much material is needed, the area equation helps you visualize this in action.

Definitions & Key Concepts

Learn essential terms and foundational ideas that form the basis of the topic.

Key Concepts

  • Quadrilaterals: Polygons with four sides.

  • Angles in Quadrilaterals: Sum equals 360Β°.

  • Properties of Parallelograms: Opposite sides are equal and parallel, diagonals bisect each other.

  • Area Formulas: Unique formulas based on quadrilateral types.

Examples & Real-Life Applications

See how the concepts apply in real-world scenarios to understand their practical implications.

Examples

  • Example: If a quadrilateral has angles measuring 90Β°, 80Β°, and 60Β°, then the fourth angle is 360Β° - (90 + 80 + 60) = 130Β°.

  • Example: Calculate the area of a rectangle with length 8 cm and width 5 cm: Area = Length Γ— Width = 8 cm Γ— 5 cm = 40 cmΒ².

Memory Aids

Use mnemonics, acronyms, or visual cues to help remember key information more easily.

🎡 Rhymes Time

  • Four sides make a quadrilateral's call, 360Β° angles, add them all!

πŸ“– Fascinating Stories

  • In a quiet village, a clever owl named Sir Parallelogram loved to remind everyone that opposites attract, just like his equal sides.

🧠 Other Memory Gems

  • Remember 'PARA' in parallel for Parallelogram, as in 'Parallel sides are Always Equal'.

🎯 Super Acronyms

Multiplying 'BASE' for area formula

  • B: = Base1 + Base2
  • A: = Area = (1/2) Γ— B Γ— Height.

Flash Cards

Review key concepts with flashcards.

Glossary of Terms

Review the Definitions for terms.

  • Term: Quadrilateral

    Definition:

    A polygon with four sides, four vertices, and four angles.

  • Term: Parallelogram

    Definition:

    A quadrilateral with opposite sides that are parallel and equal.

  • Term: Area

    Definition:

    The measure of space inside a shape, calculated differently based on the shape's type.

  • Term: Diagonal

    Definition:

    A line segment connecting two non-adjacent vertices in a polygon.

  • Term: Interior Angles

    Definition:

    The angles formed by the sides of a polygon inside the shape.