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Today, we are going to explore projectile motion! Can anyone tell me what a projectile is?
Isnβt it anything that is thrown or projected into the air?
Exactly, Student_1! A projectile can be a football, baseball, or any object in flight after being thrown. Projectile motion can be broken down into two main components. What are those?
Is it the horizontal and vertical motions?
Yes! The horizontal direction has constant velocity, while the vertical direction is influenced by gravity. What can we say about acceleration in these two motions?
The horizontal motion has zero acceleration!
Correct! And in the vertical direction, we have constant acceleration due to gravity, which is about -9.8 m/sΒ². Remember the acronym GAVβGravity Affects Vertical.
To summarize, projectile motion involves both horizontal and vertical components with different characteristics. Letβs explore how to calculate different aspects of this motion next.
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Now, letβs dive into some equations! We start with the initial velocity componentsβcan anyone express how we derive those from the launch angle?
We use trigonometric functions, right? Like sin and cos?
Absolutely, Student_4! We find the horizontal component as vββ = vβ cos ΞΈβ and the vertical component as vβα΅§ = vβ sin ΞΈβ. Can someone remind us about the equations for position as functions of time?
The x-position is x = vββ t, and for y, it's y = vβα΅§ t - (1/2) g tΒ².
Perfect! The horizontal distance x is a linear function of time while the vertical distance y forms a parabola. Let's connect these points to visualize the projectile's path next.
Can you explain how to find the shape of the path?
Good question! By eliminating time between the x and y equations, we derive a parabolic equation, which shows that the motion follows a parabolic path. Remember to think 'parabola' when calculating range or height!
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Letβs determine how long a projectile is in the air. What do we need to think about?
It depends on the initial vertical velocity and gravity.
Exactly! We use the formula Tα΅’ = 2 (vβ sin ΞΈβ) / g. What pattern do you notice in this formula?
The flight time is double the time to reach the maximum height!
Right again! And what about the horizontal range, R? How do we calculate that?
R = (vβ cos ΞΈβ)(Tα΅’)?
Very good! The horizontal range shows how far the projectile travels before returning to the same vertical level. Remember, R is maximum at a 45Β° launch angle!
In summary, weβve covered key equations for time of flight and horizontal range. Itβs all connected back to initial launch conditions and the effects of gravity.
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Letβs talk about some real-world applications of projectile motion! Can you think of where we see this in action?
Sports, like basketball and soccer!
Exactly, and in engineering too! Understanding these principles allows us to design better roller coasters and even plan space missions. Can anyone share how we might use these equations in a sports scenario?
If we know the speed and angle of a football kick, we can predict where it will land!
Right! We can optimize the kick for distance by adjusting the angle. Just remember, the angle plays a crucial role! Thatβs why many athletes practice getting the best angle for maximum range.
To conclude this session, weβve linked theoretical aspects of projectile motion to practical applications, highlighting the importance of understanding this physics concept.
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This section discusses projectile motion, where an object follows a parabolic trajectory due to the independence of horizontal motion (constant velocity) and vertical motion (constant acceleration due to gravity). Key formulas for calculating range, maximum height, and time of flight are derived, and the impact of launch angle on these parameters is explored.
Projectile motion describes the motion of an object that is projected into the air and is influenced by gravity. It can be decomposed into two independent components: horizontal motion, which occurs at a constant velocity, and vertical motion, which experiences constant acceleration due to gravity.
Using the equations of motion, we define variables such as the initial velocity (), launch angle (o), and gravitational acceleration (g). The horizontal distance traveled, known as the range (R), the time of flight (Tf), and the maximum height (hm) can all be calculated with specific equations derived from the initial conditions. Notably, the path traced by the projectile is a parabola, distinctly characterized by its launch angle.
Understanding these principles and equations is critical for analyzing various real-world projectile motions, including sports, engineering applications, and other scenarios involving flights of objects.
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As an application of the ideas developed in the previous sections, we consider the motion of a projectile. An object that is in flight after being thrown or projected is called a projectile. Such a projectile might be a football, a cricket ball, a baseball or any other object.
Projectile motion refers to the movement of an object that has been thrown or projected into the air, where it is influenced only by gravity and air resistance. Common examples include sports balls during games, where they follow a curved path. Unlike an object that simply drops straight down, projectiles follow a specific trajectory due to their initial launch speed and angle.
Imagine throwing a basketball towards the hoop. From the moment you release the ball, it is a projectile. It follows a curved path in the air until gravity pulls it back down to the ground, similar to how a thrown paper airplane glides through the air before landing.
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The motion of a projectile may be thought of as the result of two separate, simultaneously occurring components of motions. One component is along a horizontal direction without any acceleration and the other along the vertical direction with constant acceleration due to the force of gravity.
In projectile motion, the horizontal and vertical motions are independent of one another. The horizontal motion remains constant because there is no acceleration acting on it (assuming no air resistance), while the vertical motion is influenced by gravity. This means if you throw an object at an angle, it travels forward while also falling due to gravity, resulting in a curved path.
Think about water from a garden hose that's held at an angle. The water flows out straight away (horizontal motion), while it falls towards the ground (vertical motion). The combination of these two movements creates a parabolic arc, similar to how a projectile behaves in the air.
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Suppose that the projectile is launched with velocity vβ that makes an angle ΞΈβ with the x-axis as shown in Fig. 3.16. The components of initial velocity vβ are: vox = vβ cos ΞΈβ, voy = vβ sin ΞΈβ.
When a projectile is launched, it has an initial velocity that can be broken down into two components: horizontal (vox) and vertical (voy). The horizontal component is found using cosine due to its relationship with the angle ΞΈβ, while the vertical component is calculated using sine. These components help in understanding how fast the projectile moves in both directions.
Imagine a person throwing a ball to knock over a stack of cans. The speed at which they throw the ball can be divided into how far it goes forward (horizontal) and how high it goes in the air (vertical). Knowing these speeds helps them adjust their throw to hit the target accurately.
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After the object has been projected, the acceleration acting on it is that due to gravity which is directed vertically downward: a = j = -g, Or, ax = 0, ay = -g.
Once the projectile is in the air, the only acceleration it experiences is due to gravity, which pulls it downwards at a constant rate (-g, approximately 9.8 m/sΒ²). There is no horizontal acceleration because, in the absence of air resistance, the horizontal motion continues at a constant speed.
Consider a skydiver jumping out of a plane. Initially, they travel forward quickly due to their jump, but the only force acting on them after they jump is gravity, which constantly pulls them downward until they deploy their parachute.
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What is the shape of the path followed by the projectile? This can be seen by eliminating the time between the expressions for x and y as given in Eq. (3.37). We obtain: (y) = (x tan ΞΈβ) - (g/2(vβΒ² cosΒ² ΞΈβ)) xΒ².
The line equation derived from combining the horizontal and vertical positions leads to a parabolic trajectory. This means that when we plot the projectile's path on a graph, it takes the shape of a curve instead of a straight line, reflecting the influence of gravity as it acts downwards.
Think of how a fountain sprays water into the air. The water forms a beautiful arc due to the force of the water pressure (initial velocity) and the pull of gravity, which pulls the water back down, creating a parabolic shape.
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The time taken to reach the maximum height is given by tm = vo sin ΞΈβ/g. The total time Tf during which the projectile is in flight can be obtained by putting y = 0 in Eq. (3.37). We get: Tf = 2 (vo sin ΞΈβ)/g.
To find how long a projectile stays in the air, we first calculate the time to reach its highest point (when its vertical velocity is zero). The total time in flight is double that because of symmetry β it takes the same time to come down as it does to go up. The formula allows us to calculate the times based on initial velocity and launch angle.
Imagine launching a toy rocket straight into the air. The time it takes to go up before stopping momentarily and then falling back down can be predicted using these formulas based on how hard you pushed it at the start.
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The horizontal distance travelled by a projectile from its initial position (x = y = 0) to the position where it passes y = 0 during its fall is called the horizontal range R. It is the distance travelled during the time of flight Tf.
The range is how far the projectile travels horizontally before it lands again at the same vertical level it was launched from. The formula for calculating range shows that it depends on the initial speed and the angle of launch. If we maximize these parameters, we can determine the furthest distance the projectile can go.
Picture throwing a frisbee. The distance it flies before it lands on the ground is its range, which can be affected by how hard you throw it and at what angle you throw it. If you want it to go the furthest, there's a specific angle (around 45Β°) to aim for.
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Key Concepts
Independence of Motion: Horizontal motion occurs at constant velocity; vertical motion has constant acceleration due to gravity.
Projectile Path: The trajectory of a projectile is parabolic.
Effects of Launch Angle: The range and maximum height are affected by the launch angle.
See how the concepts apply in real-world scenarios to understand their practical implications.
Example: A cricket ball is thrown at a speed of 28 m/s at a 30Β° angle above the horizontal. You can find its max height and range using the formulas derived.
Use mnemonics, acronyms, or visual cues to help remember key information more easily.
To throw a projectile high and far, angle up is the way you are!
Imagine a football player calculating how to throw the ball to score a touchdown; they need the perfect angle and speed!
To find the range, remember GOT: G for gravity, O for object, T for trajectory.
Review key concepts with flashcards.
Review the Definitions for terms.
Term: Projectile
Definition:
An object that is in flight after being thrown or projected.
Term: Range (R)
Definition:
The horizontal distance traveled by a projectile.
Term: Time of Flight (Tα΅’)
Definition:
The duration for which a projectile is in the air before returning to the same vertical level.
Term: Maximum Height (hα΅’)
Definition:
The highest vertical position reached by the projectile.