8.3 - Pressure Distribution Equations
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Understanding Pressure in Fluids
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Today, we're going to talk about pressure in fluids at rest. What do you think happens to pressure when a fluid isn't moving?
I think pressure builds up wherever there’s weight from the liquid above.
Absolutely! We see that pressure is transmitted throughout the fluid. Let's explore the relationship using the equation P = P(x, y, z). Any questions about that?
Why do we ignore shear stresses when the fluid is at rest?
Good question! Shear stresses are indeed zero when fluids are stationary since the fluid layers don't slide over each other.
So only normal stresses from pressure apply?
Correct! Recall also Pascal's Law: pressure acts perpendicular to the surface. Always remember P for 'Pressure,' which is crucial for fluids.
In summary, pressure in a resting fluid is influenced solely by the weight of the fluid above it, with shear stresses being negligible.
Hydrostatic Equations
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Continuing from our last meeting, let’s derive the hydrostatic equations. What can we conclude about the force acting on our control volume?
It should balance out, right? Weight of the liquid above equals the pressure force acting down?
Exactly! We use the control volume approach to show that the net force equals zero when the fluid is static. Can anyone remind me what structure we use to depict this relationship?
We depict it using gradients in each direction?
Good! For a fluid at rest, the derivatives of pressure with respect to x and y become zero, meaning pressure only changes vertically. This gives us our hydrostatic equation!
Could we illustrate that with actual values or a depth?
Definitely! For a height 'z', pressure can be expressed as P = ρgz, where ρ is density and g is gravitational acceleration. You see how it all ties together? Remember using 'Pi' for pressure helps here: it symbolizes the significance of depth.
In conclusion, pressure increases with depth, calculated using our hydrostatic equation. Make sure to visualize this—pressure isn't uniform but varies linearly with depth.
Understanding Gauge and Absolute Pressure
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Now, let's clarify the difference between gauge pressure and absolute pressure. Who wants to take a shot?
Gauge pressure measures above atmospheric, while absolute includes atmospheric pressure, right?
Exactly! Gauge pressure is relevant in practical applications, like tire pressure. Therefore, we must always indicate if a pressure is gauge or absolute.
How do we convert gauge to absolute?
To find absolute pressure, simply add atmospheric pressure to your gauge reading: P_absolute = P_gauge + P_atmospheric. Easy mnemonic: 'Absolute is Always Above the Atmosphere.'
And what about vacuum pressure?
Great question! Vacuum pressure is measured below atmospheric pressure. It's always expressed as a negative gauge. So through 'V' for vacuum, remember: it pulls us down from the standard pressure!
Summarizing, absolute pressure accounts for all impacts while gauge focuses on the pressure above atmosphere. Grasping this foundation allows proper application in various engineering designs.
Introduction & Overview
Read summaries of the section's main ideas at different levels of detail.
Quick Overview
Standard
The section examines how to obtain the pressure distribution in stationary fluids, identifying key components such as control volumes and the effects of gravity. It further explains the concepts of absolute pressure, gauge pressure, and the hydrostatic equation, enhancing our understanding of pressure variation in fluids at rest.
Detailed
Detailed Summary of Pressure Distribution Equations
In this section, we explore how pressure fields behave in a fluid at rest, denoting pressure as a function of three Cartesian coordinates (P = P(x, y, z)). Initially, we consider a simplified control volume, where shear stress is zero, leading us to focus solely on normal stress acting as pressure. The control volume is depicted as a geometrical shape with volume defined by Lx * Ly * Lz, where Lx, Ly, and Lz are the dimensions along the x, y, and z axes respectively.
Assuming a point at the centroid of this parallelepiped, we denote the pressure at this point as P(x, y, z) while gravity acts as a body force on it. We examine surface forces, with gravity contributing to pressure distribution.
Using Pascal's law, we note that pressure acts normal to surfaces. A Taylor series expansion approximates the distance from this point to the pressure acting on the surface, leading us to understand that pressure is predominantly influenced by gravitational effects.
Equating body force and surface force yields the hydrostatic equilibrium equations, which outline that the pressure gradient in a stationary fluid is directly proportional to the weight of the fluid above the examined point; thus, we derive a linear pressure distribution with depth.
Next, we differentiate between absolute pressure (measured from a complete vacuum) and gauge pressure (measured relative to local atmospheric pressure), emphasizing their practical applications in various engineering scenarios. The section culminates in the hydrostatic equations that describe pressure variations under these influences, highlighting their importance in engineering and natural phenomena.
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Understanding Pressure in Resting Fluids
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Now if I go for the next ones that how to get the pressure field when fluid is at the rest. That means I am just looking the what could be the functions of the P, P = P(x, y, z). If it that it is now again I am considering a very simple case, let us consider a control volume like this okay. This is what my control volume. As I said it when the fluid is at rest the shear stress become zero. So there is no shear stress component on this fluid plane. Only this normal stress which is as equivalent to the pressure will act over this control surface.
Detailed Explanation
In a fluid at rest, we analyze how pressure behaves. The function P depends on three variables: x, y, and z, which represent the fluid's positional coordinates in a 3D space. When a fluid is static, shear stress (which often manifests in flowing conditions) becomes zero, meaning there's no sliding or deformation within the fluid. The only stress acting on any surface within this control volume is the normal stress, which we often refer to as pressure. Thus, pressure acts uniformly on the surface of the control volume.
Examples & Analogies
Imagine a glass of water sitting on a table. The water is at rest, and the only force acting on the bottom of the glass is the weight of the water above it, pushing down due to gravity. The pressure at the bottom of the glass is just the weight of the water divided by the glass’s area, and there are no other forces trying to move the water sideways.
Force Components in Control Volume
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There are three Cartesian directions of x, y, and z directions and I am considering a point which is just a centroid of the parallelepiped is this thing. The pressure at the centre of the fluid control volume is assumed to be P (x, y, z). At that point, the gravity force is acting it which is the body force component.
Detailed Explanation
We define a control volume as a three-dimensional space (the parallelepiped) where we measure certain properties of the fluid, including pressure. The centroid of this shape is where we specifically analyze pressure, denoted as P(x,y,z). In addition to normal stress, we also consider gravity, which acts as a body force. This means it influences the fluid at all points within our control volume by causing the fluid to exert downward pressure proportional to its weight.
Examples & Analogies
Think of a cube of jelly resting on a plate. The jelly's weight causes it to press down on the plate, creating pressure at the plate's surface beneath the jelly. Here, the jelly's weight is analogous to the gravity acting on our control volume, and the pressure at the plate represents the normal stress acting on the surface.
Pressure Distribution and Pascal’s Law
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So we can have two force components. One is the surface force component and other is body force. The body force components if you look it that it will be unit weight multiply the volume of the control volume, which is simple things. The control volumes, the volume is this much and the unit is is the density and g stands for accelerations due to gravity.
Detailed Explanation
In our control volume, we identify two forces acting on the fluid: surface forces (like pressure) and body forces (like gravity). The body force acting on the control volume due to gravity is calculated by multiplying the fluid's unit weight (density times acceleration due to gravity) by the volume of the control volume. This relationship aligns with Pascal's Law, which states that pressure applied to a confined fluid will be transmitted undiminished throughout the fluid.
Examples & Analogies
Consider a balloon filled with water. If you squeeze the balloon at one point, the water inside doesn't just compress at that point; it pushes out evenly in all directions. This illustrates Pascal's Law: the pressure is distributed uniformly throughout the fluid in the balloon.
Pressure Gradient and Force Components
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Now if you look it over this control volume, all these pressure is going to act it as Pascal law says that pressure acts normal to the surface.
Detailed Explanation
According to Pascal’s Law, pressure at any point within a fluid at rest states that the pressure acts perpendicularly to the surfaces it contacts. This applies to our control volume at all faces where pressure is acting, ensuring that the net effect of these pressure forces affects the fluid's behavior. The gradient of pressure can be described mathematically as the change in pressure over the distance, providing insight into how the pressures are distributed inside and outside the volume.
Examples & Analogies
Imagine you're swimming underwater. As you go deeper, you notice increased pressure against your body, which evenly presses on all sides. This is an application of Pascal’s Law, where pressure increases with depth in the water, acting perpendicularly against all surfaces of your body continuously.
Hydrostatic Equations and Gravity Effect
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We can derive the pressure distribution equations which in vector forms and let we simplify that equations which earlier we consider the acceleration due to gravity is a vector.
Detailed Explanation
When we derive the equations for pressure distribution, we conceptualize gravitational acceleration as a vector quantity that can point in the direction opposite to fluid motion. By aligning gravity along one of our coordinate axes (commonly the z-axis), we can separate the hydrostatic pressure equations. This allows us to analyze how pressure behaves with depth in the fluid, illustrating that pressure increases linearly with the elevation within the fluid's vertical direction due to gravitational pull.
Examples & Analogies
Think of a tall glass of soda. As you drink the soda down, the liquid at the top exerts pressure due to gravity on the soda below. The deeper you go in that soda, the more pressure you feel, equivalent to opening a soda can at high altitudes where less pressure builds up compared to when you're at sea level.
Capillary Effect and Pressure Measurement
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Now let me come to the mercury barometer case with a very simplified same capability concept what we used to measure the atmospheric pressure.
Detailed Explanation
The mercury barometer utilizes the capillary effect to measure atmospheric pressure. It consists of a tube filled with mercury, inverted into a dish of mercury. The height of the mercury column indicates the pressure of the atmosphere pushing down on the mercury in the dish, balancing the weight of the mercury column. This relationship evidences how pressure can be quantified using the height of a liquid column — linking the physical properties of liquids to pressure measurement.
Examples & Analogies
Imagine a straw that you put into a glass of water. When you put your finger over the straw's top and lift it out, the water stays inside the straw because of atmospheric pressure holding it up. This is similar to how a mercury barometer works; the weight of the mercury must be balanced by the atmospheric pressure exerted on the mercury in the dish.
Key Concepts
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Pressure Distribution: Pressure exists in a fluid at rest and is influenced by gravitational force.
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Hydrostatic Equilibrium: In a fluid at rest, pressure increases linearly with depth.
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Difference Between Gauge and Absolute Pressure: Gauge pressure is above atmospheric pressure while absolute pressure includes atmospheric pressure.
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Understanding Control Volumes: Control volumes are essential for analyzing fluid behavior and deriving equations.
Examples & Applications
A mercury barometer measures atmospheric pressure; the height of mercury changes depending on atmospheric pressure.
In a lake where the fluid is at rest, the pressure at different points along the same horizontal level is equal, demonstrating hydrostatic pressure principles.
Memory Aids
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Rhymes
Pressure at rest, it soars with depth, a fluid's layout, nature's wealth.
Stories
Imagine a lake where fish play, the deeper you go, the more pressure at bay!
Memory Tools
PAG: Pressure (P), Atmospheric (A), Gauge (G) to remember types of pressure.
Acronyms
H.P.E. - Hydrostatic Pressure Equilibrium
Pressure changes with depth.
Flash Cards
Glossary
- Control Volume
A defined region in space where we analyze fluid behavior, particularly forces and pressure.
- Hydrostatic Pressure
The pressure exerted by a fluid at equilibrium due to the force of gravity.
- Gauge Pressure
Pressure relative to local atmospheric pressure; measurable above atmospheric conditions.
- Absolute Pressure
Total pressure measured including atmospheric pressure; zero reference is absolute vacuum.
- Pressure Gradient
The rate of change of pressure in a fluid with respect to distance.
- Pascal's Law
Principle stating that pressure applied to an enclosed fluid is transmitted undiminished in all directions.
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