11.6 - Important Standard Fourier Transforms

Today, we'll start with the Dirac delta function. Who can tell me what the Fourier Transform of δ(t) is?

Close! It actually becomes 2πδ(ω). This shows that the delta function in time domain translates to a constant in frequency domain. Remember, the delta function is like a spike at t=0 which contains all frequencies!

Great question! It illustrates how the delta function maintains energy across the transform. Think of it as the impulse that captures all frequency components.

Exactly! It's vital in signal processing and analyzing systems.

To remember this, you could think, 'Delta is a key, open the door to frequencies.'

Now, let’s summarize: The Fourier transform of δ(t) is 2πδ(ω), linking the time domain to the frequency domain.

Next, let’s discuss exponential decay. What's the Fourier transform of f(t) = e^(-at)u(t)?

Correct! The transform is F(ω) = 1 / (a + iω) when a > 0. This represents how exponentially decaying signals exhibit behavior in frequency space.

This shape shows how the frequency spectrum is affected by the decay rate—higher decay implies a lower bandwidth. Visualize it as a dampening effect in the spectrum.

Absolutely! It's relevant in modeling decay in structures or signals too. As a mnemonic, think 'Decay dictates the play.'

To recap, the Fourier transform of e^(-at)u(t) is 1/(a + iω).

Now let's focus on the rectangular pulse function. What’s the transform for rect(t/T)?

Exactly! It is T·sinc(ωT/2). This illustrates how the rectangular pulse spreads its energy across multiple frequencies.

Such transforms help in analyzing signals in vibrations and signal processing but particularly useful in understanding pulse width modulation.

Yes! When constructing filters, understanding how the rectangular function behaves is key in frequency response design.

To help remember, think 'Rectangular responses stay wide in space and frequency.'

In summary, F(rect(t/T)) = T·sinc(ωT/2), demonstrating energy distribution.

Let's examine cosine and sine functions. What are their Fourier transforms starting with cos(ω₀t)?

Correct! This indicates that cosine has frequency peaks at both ω₀ and -ω₀, reflecting its even symmetry.

For sin(ω₀t), it is π[iδ(ω - ω₀) - δ(ω + ω₀)]. The sine function reflects odd symmetry, hence the imaginary component.

Symmetry relates to how we analyze and synthesize signals. It significantly impacts system responses!

To remember this, think 'Cosine peaks, while sine seeks to shift!'

In summary, F(cos(ω₀t)) = π[δ(ω - ω₀) + δ(ω + ω₀)] and F(sin(ω₀t)) = π[iδ(ω - ω₀) - δ(ω + ω₀)], marking their distinct frequency behaviors.